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24x^2-59x+36=0
a = 24; b = -59; c = +36;
Δ = b2-4ac
Δ = -592-4·24·36
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-5}{2*24}=\frac{54}{48} =1+1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+5}{2*24}=\frac{64}{48} =1+1/3 $
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